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NEET 2008 (AIPMT) · Kirchhoff's Laws & Measuring Instruments

Kirchhoff's Laws & Measuring Instruments question from NEET 2008 (AIPMT)

Q192NEET 2008 · AIPMTMedium

Kirchhoff's Laws & Measuring Instruments

Figure

In the circuit shown, the current through the 4 Ω\Omega resistor is 1 amp when the points P and M are connected to a d.c. voltage source. The potential difference between the points M and N is

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Answer: (b)

  1. 4 Ω4\ \Omega and 3 Ω3\ \Omega are in parallel between P and M: VPM=1×4=4 VV_{PM} = 1 \times 4 = 4\text{ V}.
  2. Lower branch: 0.5∥0.5=0.25 Ω0.5 \parallel 0.5 = 0.25\ \Omega, plus 1 Ω1\ \Omega, total 1.25 Ω1.25\ \Omega across the same 4 V.
  3. Current in lower branch =41.25=3.2 A= \frac{4}{1.25} = 3.2\text{ A}
  4. VNM=3.2×1=3.2 VV_{NM} = 3.2 \times 1 = 3.2\text{ V}
  5. So the answer is (b) 3.2 volt.
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