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JEE Main 2019 (11 Jan, Shift 2) · Kirchhoff's Laws & Measuring Instruments

Kirchhoff's Laws & Measuring Instruments question from JEE Main 2019 (11 Jan, Shift 2)

Q160JEE Main 2019 · 11 JAN · SHIFT 2Medium

Kirchhoff's Laws & Measuring Instruments

In the circuit shown, the potential difference between A and B is:

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Answer: (c)

A and B are open ends, so no current flows in $5\ \Omega$ and $10\ \Omega$ : $V_A - V_B = V_D - V_C$ .
Three cells (1 V, 2 V, 3 V), each with $1\ \Omega$ , in parallel with + towards D.
$V_D - V_C = \frac{1/1 + 2/1 + 3/1}{1 + 1 + 1} = 2\text{ V}$
So the answer is (c) 2 V.

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