In the circuit shown the ratio of quality factor and the bandwidth is | MHT CET 2023 (10 May, Shift 1)

Q65MHT CET 2023 · 10 MAY · SHIFT 1Easy

Resonance, Bandwidth & Q Factor

In the circuit shown the ratio of quality factor and the bandwidth is

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Answer: (a)

From the figure: $R = 10\ \Omega$ , $L = 3$ H, $C = 27\ \mu$ F.
$Q = \frac{1}{R}\sqrt{\frac{L}{C}} = \frac{1}{10}\sqrt{\frac{3}{27\times10^{-6}}} = \frac{1}{10}\times\frac{1000}{3} = \frac{100}{3}$
Bandwidth $= \frac{R}{L} = \frac{10}{3}\ \text{s}^{-1}$
$\frac{Q}{\text{BW}} = \frac{100/3}{10/3} = 10$ s
So the answer is (a) 10 s.

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