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MHT CET 2026 (18 Apr, Shift 1) · Combination of Inductors, LR & LC Circuits

Combination of Inductors, LR & LC Circuits question from MHT CET 2026 (18 Apr, Shift 1)

Q12MHT CET 2026 · 18 APR · SHIFT 1Difficult

Combination of Inductors, LR & LC Circuits

In the circuit shown, when the current 'ii' is 33A and increasing at the rate of 11A/s the measurement of the potential difference between A and B is 1212 V. But when the same current 33A is decreasing at the rate of 11A/s, the measured potential difference VABV_{AB} between A and B is 66V. The value of 'R' in the circuit is

Figure

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Answer: (a)

  1. Current flows from AA through RR and LL to BB, so VAB=iR+LdidtV_{AB} = iR + L\frac{di}{dt}.
  2. Increasing: 12=3R+L(1)12 = 3R + L(1)
  3. Decreasing: 6=3R−L(1)6 = 3R - L(1)
  4. Adding: 6R=18⇒R=3 Ω6R = 18 \Rightarrow R = 3\,\Omega (and L=3 HL = 3\text{ H}).
  5. So the answer is (a) 3 Ω3\,\Omega.
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