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JEE Main 2019 (10 Jan, Shift 1) · Vector Basics, Unit Vectors & Components

Vector Basics, Unit Vectors & Components question from JEE Main 2019 (10 Jan, Shift 1)

Q19JEE Main 2019 · 10 JAN · SHIFT 1Medium

Vector Basics, Unit Vectors & Components

In the cube of side ‘a’ shown in the figure, the vector from the central point of the face ABOD to the central point of the face BEFO will be -

Figure

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Answer: (b)

  1. From the figure: xx along OD, yy along OF, zz along OB.
  2. Face ABOD lies in the xzxz plane: centre G=(a2,0,a2)G = \left(\frac{a}{2}, 0, \frac{a}{2}\right).
  3. Face BEFO lies in the yzyz plane: centre H=(0,a2,a2)H = \left(0, \frac{a}{2}, \frac{a}{2}\right).
  4. GH⃗=H−G=a2(j^−i^)\vec{GH} = H - G = \frac{a}{2}(\hat{j} - \hat{i})
  5. So the answer is (b).
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