In the diagram shown, the resistance between points A and B is ' R₁ ' when an ideal diode D is forward biased and is ' R₂ ' when ideal diode D is reverse biased. The ratio R₁/R₂ is (a) 2 (b) 1 (c) 1/2 (d) 1/4

Answer: (c). Forward bias: diode is a short, so the two 30 Ω resistors are in parallel, R₁ = 15 Ω. Reverse bias: diode branch is open, so only the lower 30 Ω remains, R₂ = 30 Ω. (R₁)/(R₂) = 15/30 = 1/2 So the answer is (c) 1/2.

In the diagram shown, the resistance between points A and B is ' R₁ '… | MHT CET 2026 (15 Apr, Shift 2)

Q16MHT CET 2026 · 15 APR · SHIFT 2Medium

P-N Junction Diode

In the diagram shown, the resistance between points A and B is ' $R_1$ ' when an ideal diode D is forward biased and is ' $R_2$ ' when ideal diode D is reverse biased. The ratio $R_1/R_2$ is

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Answer: (c)

Forward bias: diode is a short, so the two $30\ \Omega$ resistors are in parallel, $R_1 = 15\ \Omega$ .
Reverse bias: diode branch is open, so only the lower $30\ \Omega$ remains, $R_2 = 30\ \Omega$ .
$\dfrac{R_1}{R_2} = \dfrac{15}{30} = \dfrac{1}{2}$
So the answer is (c) $\frac{1}{2}$ .

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P-N Junction Diode question from MHT CET 2026 (15 Apr, Shift 2)

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