In the electric field due to a charge Q, a charge q moves from point A to B. The work done is ( ε₀ = permittivity of vacuum) (a) (1)/(4πε₀)Qq/r² (b) (1)/(4πε₀)Qq/r × π/6 (c) (1)/(4πε₀)Qq/r (d) Zero

Answer: (d). A and B are on a circle of radius r about Q: an equipotential, VA = VB. W = q(VB - VA) = 0 So the answer is (d) zero.

In the electric field due to a charge Q, a charge q moves from point… | MHT CET 2023 (13 May, Shift 2)

Q36MHT CET 2023 · 13 MAY · SHIFT 2Easy

Electrostatic Potential Energy

In the electric field due to a charge $Q$ , a charge $q$ moves from point $A$ to $B$ . The work done is ( $\varepsilon_0 =$ permittivity of vacuum)

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Answer: (d)

A and B are on a circle of radius $r$ about $Q$ : an equipotential, $V_A = V_B$ .
$W = q(V_B - V_A) = 0$
So the answer is (d) zero.

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