In the figure shown below, the charge on the left plate of the 10 μ F capacitor is –30 μ C. The charge on the right plate of the 6 μ F capacitor is: (a) + 12 μ C (b) + 18 μ C (c) - 18 μ C (d) - 12 μ C

Answer: (b). Left plate of 10 is -30, so its right plate is +30 and the left plates of 6 and 4 together hold -30. 6 and 4 are in parallel (same V), so charge divides as 6:4: -18 and -12. Right plate of 6: +18. So the answer is (b) +18 μ C.

In the figure shown below, the charge on the left plate of the 10 μ F… | JEE Main 2019 (11 Jan, Shift 1)

Q80JEE Main 2019 · 11 JAN · SHIFT 1Medium

Combination of Capacitors

In the figure shown below, the charge on the left plate of the 10 $\mu$ F capacitor is –30 $\mu$ C. The charge on the right plate of the 6 $\mu$ F capacitor is:

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Answer: (b)

Left plate of $10\ \mu\text{F}$ is $-30\ \mu\text{C}$ , so its right plate is $+30\ \mu\text{C}$ and the left plates of $6$ and $4$ together hold $-30\ \mu\text{C}$ .
$6$ and $4$ are in parallel (same $V$ ), so charge divides as $6:4$ : $-18$ and $-12\ \mu\text{C}$ .
Right plate of $6\ \mu\text{F}$ : $+18\ \mu\text{C}$ .
So the answer is (b) +18 $\mu$ C.

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Combination of Capacitors question from JEE Main 2019 (11 Jan, Shift 1)

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