Combination of Resistors question from MHT CET 2025 (26 Apr, Shift 2)

Answer: (b)

1. Bridge ratio: $\dfrac{R_{AC}}{R_{CB}} = \dfrac{R_{AD}}{R_{DB}} = 1$, so it is a balanced Wheatstone bridge and no current flows in CD.
2. Path ACB is then simply $R + R = 8\ \Omega$ across the $16$ V battery.
3. $I_{ACB} = \dfrac{16}{8} = 2$ A. So the answer is (b) 2 A.