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MHT CET 2024 (2 May, Shift 2) · Kirchhoff's Laws & Measuring Instruments

Kirchhoff's Laws & Measuring Instruments question from MHT CET 2024 (2 May, Shift 2)

Q50MHT CET 2024 · 2 MAY · SHIFT 2Medium

Kirchhoff's Laws & Measuring Instruments

In the following circuit, the current flowing through zener diode is

Figure

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Answer: (b)

  1. Zener holds 88 V across R2R_2: IR2=81600=5I_{R2} = \frac{8}{1600} = 5 mA.
  2. Voltage across R1=20−8=12R_1 = 20 - 8 = 12 V: IR1=12400=30I_{R1} = \frac{12}{400} = 30 mA.
  3. Iz=IR1−IR2=30−5=25I_z = I_{R1} - I_{R2} = 30 - 5 = 25 mA
  4. So the answer is (b) 25 mA.
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