In the following circuit, the current in the 4 Ω resistance is 1.2 A. The total current ( I) flowing in the circuit is (a) 1.6 A (b) 2.4 A (c) 2.8 A (d) 3.2 A

Answer: (c). The 4 Ω and 3 Ω are in parallel, so they have the same voltage. V = I₁ R = 1.2 × 4 = 4.8 V I₂ = 4.8/3 = 1.6 A I = I₁ + I₂ = 1.2 + 1.6 = 2.8 A. So the answer is (c) 2.8 A.

In the following circuit, the current in the 4 Ω resistance is 1.2 A… | MHT CET 2026 (19 May, Shift 1)

Q3MHT CET 2026 · 19 MAY · SHIFT 1Medium

Combination of Resistors

In the following circuit, the current in the $4\ \Omega$ resistance is $1.2$ A. The total current ( $I$ ) flowing in the circuit is

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Answer: (c)

The $4\ \Omega$ and $3\ \Omega$ are in parallel, so they have the same voltage.
$V = I_1 R = 1.2 \times 4 = 4.8$ V
$I_2 = \dfrac{4.8}{3} = 1.6$ A
$I = I_1 + I_2 = 1.2 + 1.6 = 2.8$ A. So the answer is (c) $2.8$ A.

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Combination of Resistors question from MHT CET 2026 (19 May, Shift 1)

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