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MHT CET 2025 (23 Apr, Shift 1) · Kirchhoff's Laws & Measuring Instruments

Kirchhoff's Laws & Measuring Instruments question from MHT CET 2025 (23 Apr, Shift 1)

Q25MHT CET 2025 · 23 APR · SHIFT 1Medium

Kirchhoff's Laws & Measuring Instruments

In the following circuit, the current through 6 Ω6\ \Omega resistor is

Figure

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Answer: (b)

  1. The two identical cells (33 V, 3 Ω3\ \Omega each) are in parallel with like poles together.
  2. Equivalent cell: E=3E = 3 V, r=32=1.5 Ωr = \frac{3}{2} = 1.5\ \Omega.
  3. I=ER+r=36+1.5=37.5I = \frac{E}{R + r} = \frac{3}{6 + 1.5} = \frac{3}{7.5}
  4. So the answer is (b) 25\frac{2}{5} A.
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