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MHT CET 2025 (25 Apr, Shift 2) · Magnetic Field of Straight Wires

Magnetic Field of Straight Wires question from MHT CET 2025 (25 Apr, Shift 2)

Q21MHT CET 2025 · 25 APR · SHIFT 2Medium

Magnetic Field of Straight Wires

In the following figure magnitude of the magnetic field at the point pp is

Figure

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Answer: (c)

  1. Section 1 lies along a line through P, so it gives zero.
  2. Semicircle 2: μ0I4r\frac{\mu_0 I}{4r}; section 3 is semi-infinite starting directly below P: μ0I4πr\frac{\mu_0 I}{4\pi r}.
  3. Both are out of the page: B=μ0I4πr+μ0I4rB = \frac{\mu_0 I}{4\pi r} + \frac{\mu_0 I}{4r}
  4. So the answer is (c).
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