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JEE Main 2016 (9 Apr, Shift 1) · Units & Dimensions

Units & Dimensions question from JEE Main 2016 (9 Apr, Shift 1)

Q82JEE Main 2016 · 9 APR · SHIFT 1Easy

Units & Dimensions

In the following ‘I’ refers to current and other symbols have their usual meaning. Choose the option that corresponds to the dimensions of electrical conductivity:

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Answer: (c)

  1. σ=1/ρ\sigma = 1/\rho and ρ=RA/l\rho = RA/l.
  2. [R]=[V/I]=ML2T−3I−2[R] = [V/I] = \mathrm{ML^2T^{-3}I^{-2}}, so [ρ]=ML3T−3I−2[\rho] = \mathrm{ML^3T^{-3}I^{-2}}.
  3. [σ]=M−1L−3T3I2[\sigma] = \mathrm{M^{-1}L^{-3}T^3I^2}
  4. So the answer is (c).
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