In the following network, I₁ = -0.4 A, I₄ = 1 A, I₅ = 0.4 A The values of I₂, I₃ and I₆ are respectively (a) 1.4 A, 0.4 A, -0.6 A (b) 0.4 A, -0.6 A, 1.4 A (c) 1.4 A, -0.6 A, 0.4 A (d) -0.6 A, 1.4 A, 0.4 A

Answer: (c). Path through the top-left corner has no branch: I₆ = I₅ = 0.4 A. Bottom-right junction: I₁ + I₂ = I₄ ⇒ I₂ = 1 - (-0.4) = 1.4 A. Top-right junction: I₆ = I₃ + I₂ + I₁ ⇒ I₃ = 0.4 - 1.4 + 0.4 = -0.6 A. So the answer is (c) 1.4 A, -0.6 A, 0.4 A.

In the following network, I₁ = -0.4 A, I₄ = 1 A, I₅ = 0.4 A The… | MHT CET 2026 (18 Apr, Shift 2)

Q10MHT CET 2026 · 18 APR · SHIFT 2Medium

Kirchhoff's Laws & Measuring Instruments

In the following network,

$I_1 = -0.4$ A, $I_4 = 1$ A, $I_5 = 0.4$ A

The values of $I_2, I_3$ and $I_6$ are respectively

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Answer: (c)

Path through the top-left corner has no branch: $I_6 = I_5 = 0.4$ A.
Bottom-right junction: $I_1 + I_2 = I_4 \Rightarrow I_2 = 1 - (-0.4) = 1.4$ A.
Top-right junction: $I_6 = I_3 + I_2 + I_1 \Rightarrow I_3 = 0.4 - 1.4 + 0.4 = -0.6$ A.
So the answer is (c) $1.4$ A, $-0.6$ A, $0.4$ A.

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Kirchhoff's Laws & Measuring Instruments question from MHT CET 2026 (18 Apr, Shift 2)

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