Wheatstone Bridge & Metre Bridge question from MHT CET 2022 (11 Aug, Shift 2)

Answer: (d)

1. Take $V_P = V$ (positive terminal) and $V_R = 0$.
2. Branch PQR: $4$ and $4\ \Omega$, so $V_Q = \dfrac{4}{8}V = 0.5V$
3. Branch PSR: $1$ and $3\ \Omega$, so $V_S = \dfrac{3}{4}V = 0.75V$
4. $V_S > V_Q$, so current flows through G from S to Q.
5. So the answer is (d) from S to Q.