In the given circuit below inductance values of L₁, L₂ and L₃ are same. The magnetic energy stored in the entire circuit is (Ut) and that stored in the L₂ inductor is (Ul) · Ut / Ul is ______. (Ignore the mutual inductance if any) Numerical answer type. Work it out, then open the answer.

Answer: 6. L₁ carries the full current I; L₂ and L₃ are equal and in parallel, so each carries I/2. Ut = 1/2LI² + 2·1/2L(I/2)² = 3/4LI² Ul = 1/2L(I/2)² = 1/8LI² Ut/Ul = (3/4)/(1/8) = 6

In the given circuit below inductance values of L₁, L₂ and L₃ are… | JEE Main 2026 (5 Apr, Shift 1)

Q11JEE Main 2026 · 5 APR · SHIFT 1Medium

Combination of Inductors, LR & LC Circuits

In the given circuit below inductance values of $L_1, L_2$ and $L_3$ are same. The magnetic energy stored in the entire circuit is $(U_t)$ and that stored in the $L_2$ inductor is $(U_l) \cdot U_t / U_l$ is ______. (Ignore the mutual inductance if any)

Numerical answer type. Work it out, then open the answer.

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Answer: 6

$L_1$ carries the full current $I$ ; $L_2$ and $L_3$ are equal and in parallel, so each carries $I/2$ .
$U_t = \frac{1}{2}LI^2 + 2\cdot\frac{1}{2}L\left(\frac{I}{2}\right)^2 = \frac{3}{4}LI^2$
$U_l = \frac{1}{2}L\left(\frac{I}{2}\right)^2 = \frac{1}{8}LI^2$
$U_t/U_l = \frac{3/4}{1/8} = 6$

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Combination of Inductors, LR & LC Circuits question from JEE Main 2026 (5 Apr, Shift 1)

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