In the given circuit, C₁=2, C₂=0.2, C₃=2, C₄=4, C₅=2, C₆=2, The charge stored on capacitor C₄ is ____________. Numerical answer type. Work it out, then open the answer.

Answer: 4. C₃, C₄, C₅ in series: 1/C' = 1/2+1/4+1/2 ⇒ C' = 0.8. C' parallel with C₂: 0.8+0.2 = 1; in series with C₁, C₆: 1Ceq = 1/2+1+1/2 ⇒ Ceq = 0.5. Q = 0.5×10 = 5, so the middle block has V = 5/1 = 5 V. Charge on the C₃C₄C₅ chain = 0.8×5 = 4, which is the charge on C₄: 4.

In the given circuit, C₁=2, C₂=0.2, C₃=2, C₄=4, C₅=2, C₆=2, The… | JEE Main 2023 (11 Apr, Shift 2)

Q22JEE Main 2023 · 11 APR · SHIFT 2Medium

Capacitors in DC Circuits & RC

In the given circuit, $C_1=2\ \mu\text{F}, C_2=0.2\ \mu\text{F}, C_3=2\ \mu\text{F}, C_4=4\ \mu\text{F}, C_5=2\ \mu\text{F}, C_6=2\ \mu\text{F}$ , The charge stored on capacitor $C_4$ is ____________ $\mu\text{C}$ .

Numerical answer type. Work it out, then open the answer.

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Answer: 4

$C_3, C_4, C_5$ in series: $\dfrac{1}{C'} = \dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{2} \Rightarrow C' = 0.8\ \mu\text{F}$ .
$C'$ parallel with $C_2$ : $0.8+0.2 = 1\ \mu\text{F}$ ; in series with $C_1, C_6$ : $\dfrac{1}{C_{eq}} = \dfrac{1}{2}+1+\dfrac{1}{2} \Rightarrow C_{eq} = 0.5\ \mu\text{F}$ .
$Q = 0.5\times10 = 5\ \mu\text{C}$ , so the middle block has $V = \dfrac{5}{1} = 5\text{ V}$ .
Charge on the $C_3C_4C_5$ chain $= 0.8\times5 = 4\ \mu\text{C}$ , which is the charge on $C_4$ : $4\ \mu\text{C}$ .

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