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Capacitors in DC Circuits & RC question from JEE Main 2017

Q38JEE Main 2017Medium

Capacitors in DC Circuits & RC

In the given circuit diagram when the current reaches steady state in the circuit, the charge on the capacitor of capacitance C will be:

Figure

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Answer: (d)

  1. Steady state: no current through r1r_1, so current flows only through rr and r2r_2: I=Er+r2I = \dfrac{E}{r+r_2}.
  2. Capacitor (with r1r_1, no drop) is across r2r_2: VC=Er2r+r2V_C = \dfrac{Er_2}{r+r_2}
  3. Q=CVC=CEr2r+r2Q = CV_C = CE\dfrac{r_2}{r+r_2}
  4. So the answer is (d).
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