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MHT CET 2023 (12 May, Shift 1) · Series LCR Circuit

Series LCR Circuit question from MHT CET 2023 (12 May, Shift 1)

Q38MHT CET 2023 · 12 MAY · SHIFT 1Medium

Series LCR Circuit

In the given circuit, r.m.s. value of current through the resistor $R$ is

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Answer: (a)

Series circuit: same current through $R$ ; $Z = \sqrt{R^2 + (X_L - X_C)^2}$ .
$Z = \sqrt{100^2 + (200 - 100)^2} = 100\sqrt{2}\ \Omega$
$I_{rms} = \dfrac{V_{rms}}{Z} = \dfrac{200\sqrt{2}}{100\sqrt{2}} = 2\text{ A}$
So the answer is (a) $2\text{ A}$ .

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