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MHT CET 2026 (12 May, Shift 2) · Series LCR Circuit

Series LCR Circuit question from MHT CET 2026 (12 May, Shift 2)

Q6MHT CET 2026 · 12 MAY · SHIFT 2Medium

Series LCR Circuit

In the given circuit, r.m.s. value of current through the resistor $R$ is

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Answer: (b)

$Z = \sqrt{100^2 + (200 - 100)^2} = 100\sqrt{2}\ \Omega$
$I_{rms} = \frac{200\sqrt{2}}{100\sqrt{2}} = 2$ A (same through $R$ in series)
So the answer is (b) 2 A.

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