In the given circuit, the breakdown voltage of the Zener diode is 3.0 V. What is the value of Iz? (a) 3.3 mA (b) 10 mA (c) 5.5 mA (d) 7 mA

Answer: (c). Without the Zener the load would get 10 × 2/3 ≈ 6.7 V > 3 V, so the Zener holds 3 V. I = (10 - 3)/(1 kΩ) = 7 mA IL = (3)/(2 kΩ) = 1.5 mA IZ = 7 - 1.5 = 5.5 mA, so the answer is (c).

In the given circuit, the breakdown voltage of the Zener diode is 3.0… | JEE Main 2024 (29 Jan, Shift 1)

Q35JEE Main 2024 · 29 JAN · SHIFT 1Medium

Special Purpose Diodes

In the given circuit, the breakdown voltage of the Zener diode is $3.0\text{ V}$ . What is the value of $\text{I}_\text{z}$ ?

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Answer: (c)

Without the Zener the load would get $10 \times \frac{2}{3} \approx 6.7$ V $> 3$ V, so the Zener holds $3$ V.
$I = \frac{10 - 3}{1\text{ k}\Omega} = 7$ mA
$I_L = \frac{3}{2\text{ k}\Omega} = 1.5$ mA
$I_Z = 7 - 1.5 = 5.5$ mA, so the answer is (c).

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