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JEE Main 2019 (10 Jan, Shift 1) · Kirchhoff's Laws & Measuring Instruments

Kirchhoff's Laws & Measuring Instruments question from JEE Main 2019 (10 Jan, Shift 1)

Q158JEE Main 2019 · 10 JAN · SHIFT 1Medium

Kirchhoff's Laws & Measuring Instruments

In the given circuit the cells have zero internal resistance. The currents (in Amperes) passing through resistance R1 and R2 respectively, are -

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Answer: (a)

Call the top wire T and the bottom middle node M.
Left cell: going from T (left end) through $-$ to $+$ reaches M, so $V_M - V_T = 10$ V.
$R_1$ is across T and M: $I_1 = \frac{10}{20} = 0.5$ A.
Right cell: from M through $+$ to $-$ drops $10$ V, so the bottom of $R_2$ is at $V_T$ ; no p.d. across $R_2$ , so $I_2 = 0$ .
So the answer is (a) 0.5, 0.

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