Combination of Capacitors question from JEE Main 2019 (12 Apr, Shift 2)

Answer: (d)

1. The $1$ and $5\ \mu\text{F}$ are in parallel: $6\ \mu\text{F}$; in series with $4\ \mu\text{F}$: $\frac{4\times 6}{10} = 2.4\ \mu\text{F}$.
2. This branch is directly across 10 V (the $3\ \mu\text{F}$ is a separate parallel branch).
3. Branch charge $= 2.4\times 10 = 24\ \mu\text{C}$, which is the charge on the $4\ \mu\text{F}$.
4. So the answer is (d) 24 $\mu$C.