In the given circuit, the current flowing through the resistance 20 Ω is 0.3 A, while the ammeter reads 0.9 A. The value of R₁ is _________ Ω. Numerical answer type. Work it out, then open the answer.

Answer: 30. All three resistors are in parallel: V = 0.3 × 20 = 6 V. Current in 15 Ω = 6/15 = 0.4 A. The ammeter reads the total: I₁ = 0.9 - 0.3 - 0.4 = 0.2 A R₁ = 6/0.2 = 30 Ω

In the given circuit, the current flowing through the resistance 20 Ω… | JEE Main 2024 (29 Jan, Shift 2)

Q63JEE Main 2024 · 29 JAN · SHIFT 2Medium

Kirchhoff's Laws & Measuring Instruments

In the given circuit, the current flowing through the resistance $20\ \Omega$ is $0.3\text{ A}$ , while the ammeter reads $0.9\text{ A}$ . The value of $R_1$ is _________ $\Omega$ .

Numerical answer type. Work it out, then open the answer.

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Answer: 30

All three resistors are in parallel: $V = 0.3 \times 20 = 6\text{ V}$ .
Current in $15\ \Omega = \dfrac{6}{15} = 0.4\text{ A}$ .
The ammeter reads the total: $I_1 = 0.9 - 0.3 - 0.4 = 0.2\text{ A}$
$R_1 = \dfrac{6}{0.2} = 30\ \Omega$

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