In the given circuit, the current in resistance R ₃ is: (a) 2 A (b) 1.5 A (c) 1 A (d) 2.5 A

Answer: (c). R₂ ∥ R₃ = (4 × 4)/(8) = 2 Ω. Total = 2 + 2 + 1 = 5 Ω, so I = 10/5 = 2 A. Equal resistors share equally: I₃ = 2/2 = 1 A So the answer is (c) 1 A.

In the given circuit, the current in resistance R ₃ is: | JEE Main 2024 (29 Jan, Shift 2)

Q52JEE Main 2024 · 29 JAN · SHIFT 2Medium

Kirchhoff's Laws & Measuring Instruments

In the given circuit, the current in resistance R ${}_{3}$ is:

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Answer: (c)

$R_2 \parallel R_3 = \frac{4 \times 4}{8} = 2\ \Omega$ .
Total $= 2 + 2 + 1 = 5\ \Omega$ , so $I = \frac{10}{5} = 2$ A.
Equal resistors share equally: $I_3 = \frac{2}{2} = 1$ A
So the answer is (c) 1 A.

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