In the given circuit, the current through zener diode is: (a) 5.5 mA (b) 6.7 mA (c) 2.5 mA (d) 3.3 mA

Answer: (d). Without the Zener, R₂ would get 15 × (1500)/(2000) = 11.25 V > 10 V, so the Zener holds 10 V. I = (15 - 10)/(500) = 10 mA I₂ = (10)/(1500) = 6.67 mA IZ = 10 - 6.67 = 3.3 mA, so the answer is (d).

In the given circuit, the current through zener diode is: | JEE Main 2018 (16 Apr, Shift 1)

Q85JEE Main 2018 · 16 APR · SHIFT 1Medium

Special Purpose Diodes

In the given circuit, the current through zener diode is:

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Answer: (d)

Without the Zener, $R_2$ would get $15 \times \frac{1500}{2000} = 11.25$ V $> 10$ V, so the Zener holds $10$ V.
$I = \frac{15 - 10}{500} = 10$ mA
$I_2 = \frac{10}{1500} = 6.67$ mA
$I_Z = 10 - 6.67 = 3.3$ mA, so the answer is (d).

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