In the given circuit the current through Zener Diode is close to: (a) 0.0 mA (b) 6.7 mA (c) 4.0 mA (d) 6.0 mA

Answer: (a). Without the Zener, the voltage across R₂ = 1500 Ω is 12 × (1500)/(2000) = 9 V (the extra load R₂ only lowers it further). 9 V < VZ = 10 V, so the Zener never reaches breakdown. So the answer is (a) 0.0 mA.

In the given circuit the current through Zener Diode is close to: | JEE Main 2019 (11 Jan, Shift 1)

Q83JEE Main 2019 · 11 JAN · SHIFT 1Medium

Special Purpose Diodes

In the given circuit the current through Zener Diode is close to:

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Answer: (a)

Without the Zener, the voltage across $R_2 = 1500\ \Omega$ is $12 \times \frac{1500}{2000} = 9$ V (the extra load $R_2$ only lowers it further).
$9$ V $< V_Z = 10$ V, so the Zener never reaches breakdown.
So the answer is (a) $0.0$ mA.

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