In the given circuit the sliding contact is pulled outwards such that electric current in the circuit changes at the rate of 8 A/s. At an instant when R is 12 Ω, the value of the current in the circuit will be ________ A. Numerical answer type. Work it out, then open the answer.

Answer: 3. Pulling the contact out increases R, so current decreases: dI/dt = -8 A/s. KVL: E - LdI/dt = IR ⇒ 12 + 3×8 = 12 I I = 36/12 = 3 A

In the given circuit the sliding contact is pulled outwards such that… | JEE Main 2025 (23 Jan, Shift 1)

Q17JEE Main 2025 · 23 JAN · SHIFT 1Medium

Combination of Inductors, LR & LC Circuits

In the given circuit the sliding contact is pulled outwards such that electric current in the circuit changes at the rate of $8\text{ A/s}$ . At an instant when R is $12\,\Omega$ , the value of the current in the circuit will be ________ A.

Numerical answer type. Work it out, then open the answer.

Show answer and solution

Answer: 3

Pulling the contact out increases $R$ , so current decreases: $\frac{dI}{dt} = -8\text{ A/s}$ .
KVL: $E - L\frac{dI}{dt} = IR \Rightarrow 12 + 3\times8 = 12 I$
$I = \frac{36}{12} = 3\text{ A}$

Report a mistake

Combination of Inductors, LR & LC Circuits question from JEE Main 2025 (23 Jan, Shift 1)

More questions on Combination of Inductors, LR & LC Circuits