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JEE Main 2024 (8 Apr, Shift 1) · Cells: EMF, Internal Resistance & Combinations

Cells: EMF, Internal Resistance & Combinations question from JEE Main 2024 (8 Apr, Shift 1)

Q11JEE Main 2024 · 8 APR · SHIFT 1Medium

Cells: EMF, Internal Resistance & Combinations

In the given circuit, the terminal potential difference of the cell is:

Figure

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Answer: (c)

  1. The two 4 Ω4\ \Omega resistors are in parallel: R=2 ΩR = 2\ \Omega
  2. I=32+1=1 AI = \frac{3}{2 + 1} = 1\text{ A}
  3. V=E−Ir=3−1×1=2 VV = E - Ir = 3 - 1 \times 1 = 2\text{ V}. So the answer is (c) 2 V.
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