In the given circuit, the value of current IL will be ____________ mA. (When RL = 1k Ω) Numerical answer type. Work it out, then open the answer.

Answer: 5. Without the Zener the load gets 10 × (1000)/(1800) ≈ 5.6 V > 5 V, so the Zener conducts and holds 5 V. IL = (5)/(1 kΩ) = 5 mA

In the given circuit, the value of current IL will be ____________… | JEE Main 2022 (24 Jun, Shift 2)

Q56JEE Main 2022 · 24 JUN · SHIFT 2Medium

Special Purpose Diodes

In the given circuit, the value of current IL will be ____________ mA. (When RL = 1k $\Omega$ )

Numerical answer type. Work it out, then open the answer.

Show answer and solution

Answer: 5

Without the Zener the load gets $10 \times \frac{1000}{1800} \approx 5.6$ V $> 5$ V, so the Zener conducts and holds $5$ V.
$I_L = \frac{5}{1\text{ k}\Omega} = 5$ mA

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