In the given circuit, when S₁ is closed, the capacitor gets fully charged. Now S₁ is open and S₂ is closed. Then (a) there is no exchange of energy between L and C. (b) the current in the circuit is in the same direction. (c) the instantaneous current in the circuit may be V(√(C/L)). (d) the energy stored in the circuit is purely in the form of magnetic energy.

Answer: (c). With S₂ closed, the charged capacitor discharges through L: an LC oscillator. Energy keeps swapping between C (electric) and L (magnetic), and the current reverses every half cycle, so (a), (b), (d) are wrong. At the instant all energy is magnetic: 1/2CV² = 1/2LI² ⇒ I = V√(C/L) So the answer is (c).

In the given circuit, when S₁ is closed, the capacitor gets fully… | MHT CET 2024 (2 May, Shift 1)

Q9MHT CET 2024 · 2 MAY · SHIFT 1Easy

LC Oscillations

In the given circuit, when $S_1$ is closed, the capacitor gets fully charged. Now $S_1$ is open and $S_2$ is closed. Then

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Answer: (c)

With $S_2$ closed, the charged capacitor discharges through $L$ : an LC oscillator.
Energy keeps swapping between $C$ (electric) and $L$ (magnetic), and the current reverses every half cycle, so (a), (b), (d) are wrong.
At the instant all energy is magnetic: $\frac{1}{2}CV^2 = \frac{1}{2}LI^2 \Rightarrow I = V\sqrt{\frac{C}{L}}$
So the answer is (c).

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LC Oscillations question from MHT CET 2024 (2 May, Shift 1)

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