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NEET 2015 (AIPMT) · P-N Junction Diode

P-N Junction Diode question from NEET 2015 (AIPMT)

Q98NEET 2015 · AIPMTEasy

P-N Junction Diode

In the given figure, a diode D is connected to an external resistance R = 100 $\Omega$ and an e.m.f. of 3.5 V. If the barrier potential developed across the diode is 0.5 V, the current in the circuit will be

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Answer: (c)

The diode is forward biased; voltage left for the resistor $= 3.5 - 0.5 = 3.0\text{ V}$ .
$I = \dfrac{3.0}{100} = 0.03\text{ A}$
So the answer is (c) $30\text{ mA}$ .

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