In the given figure an ammeter A consists of a 240 Ω coil connected in parallel to a 10 Ω shunt. The reading of the ammeter is ________ mA. Numerical answer type. Work it out, then open the answer.

Answer: 160. Ammeter resistance = (240 × 10)/(250) = 9.6 Ω Total resistance = 140.4 + 9.6 = 150 Ω I = 24/150 = 0.16 A Answer: 160 mA

In the given figure an ammeter A consists of a 240 Ω coil connected… | JEE Main 2024 (6 Apr, Shift 2)

Q72JEE Main 2024 · 6 APR · SHIFT 2Medium

Kirchhoff's Laws & Measuring Instruments

In the given figure an ammeter A consists of a $240\ \Omega$ coil connected in parallel to a $10\ \Omega$ shunt. The reading of the ammeter is ________ $\text{mA}$ .

Numerical answer type. Work it out, then open the answer.

Show answer and solution

Answer: 160

Ammeter resistance $= \frac{240 \times 10}{250} = 9.6\ \Omega$
Total resistance $= 140.4 + 9.6 = 150\ \Omega$
$I = \frac{24}{150} = 0.16\text{ A}$
Answer: 160 mA

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