In the given potentiometer circuit arrangement, the balancing length… | JEE Main 2021 (25 Jul, Shift 2)

Q58JEE Main 2021 · 25 JUL · SHIFT 2Medium

Potentiometer

In the given potentiometer circuit arrangement, the balancing length AC is measured to be 250 cm. When the galvanometer connection is shifted from point (1) to point (2) in the given diagram, the balancing length becomes 400 cm. The ratio of the emf of two cells, $\frac{\varepsilon_1}{\varepsilon_2}$ is:

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Answer: (a)

With G at point (1), only $\varepsilon_1$ is in the loop: $\varepsilon_1 = k(250)$ .
With G at point (2), both cells aid each other: $\varepsilon_1+\varepsilon_2 = k(400)$ .
$\varepsilon_2 = k(150)$
$\dfrac{\varepsilon_1}{\varepsilon_2} = \dfrac{250}{150} = \dfrac{5}{3}$
So the answer is (a) $\dfrac{5}{3}$ .

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