In the given reaction zXA → z+1YA → z-1KA-4 → z-1KA-4 radioactive radiations are emitted in the sequence (a) α, β, γ (b) β, α, γ (c) γ, α, β (d) β, γ, α

Answer: (b). X → Y: Z up by 1, A same, so β⁻. Y → K: A down by 4, Z down by 2, so α. K → K: no change in A or Z (de-excitation), so γ. So the answer is (b) β, α, γ.

In the given reaction zXA → z+1YA → z-1KA-4 → z-1KA-4 radioactive… | MHT CET 2024 (15 May, Shift 2)

Q10MHT CET 2024 · 15 MAY · SHIFT 2Medium

Radioactive Decays: Alpha, Beta, Gamma

In the given reaction

${}_{z}\text{X}^{A} \rightarrow {}_{z+1}\text{Y}^{A} \rightarrow {}_{z-1}\text{K}^{A-4} \rightarrow {}_{z-1}\text{K}^{A-4}$

radioactive radiations are emitted in the sequence

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Answer: (b)

$X \to Y$ : $Z$ up by 1, $A$ same, so $\beta^-$ .
$Y \to K$ : $A$ down by 4, $Z$ down by 2, so $\alpha$ .
$K \to K$ : no change in $A$ or $Z$ (de-excitation), so $\gamma$ .
So the answer is (b) $\beta, \alpha, \gamma$ .

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Radioactive Decays: Alpha, Beta, Gamma question from MHT CET 2024 (15 May, Shift 2)

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