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MHT CET 2021 (23 Sep, Shift 1) · Biprism, Thin Films & Other Devices

Biprism, Thin Films & Other Devices question from MHT CET 2021 (23 Sep, Shift 1)

Q20MHT CET 2021 · 23 SEP · SHIFT 1Easy

Biprism, Thin Films & Other Devices

In the interference experiment using a biprism, the distance of the slits from the screen is increased by $25\%$ and the separation between the slits is halved. If ' $W$ ' represents the original fringewidth, the new fringewidth is

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Answer: (b)

$W = \frac{\lambda D}{d}$ .
$D' = 1.25D$ , $d' = 0.5d$ : $W' = \frac{1.25}{0.5}W = 2.5W$ .
So the answer is (b) 2.5 W.

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