In the logic circuit diagram, when all the four inputs A, B, C, D are one, the outputs Y₁, Y₂, Y₃ are respectively (1, 1, 0). When all the inputs A, B, C, D are changed to 'zero', the outputs Y₁, Y₂, Y₃ respectively change to (a) (0, 1, 0) (b) (0, 0, 1) (c) (1, 1, 0) (d) (1, 1, 1)

Answer: (b). Y₁ = A + B, Y₂ = C · D = C · D, Y₃ = Y₁ + Y₂. Check: all inputs 1 give (1, 1, 0), as stated. All inputs 0: Y₁ = 0, Y₂ = 0, Y₃ = 0 + 0 = 1. So the answer is (b) (0, 0, 1).

In the logic circuit diagram, when all the four inputs A, B, C, D are… | MHT CET 2024 (9 May, Shift 1)

Q64MHT CET 2024 · 9 MAY · SHIFT 1Medium

Logic Gates

In the logic circuit diagram, when all the four inputs $\mathrm{A}, \mathrm{B}, \mathrm{C}, \mathrm{D}$ are one, the outputs $\mathrm{Y}_1, \mathrm{Y}_2, \mathrm{Y}_3$ are respectively $(1, 1, 0)$ . When all the inputs $\mathrm{A}, \mathrm{B}, \mathrm{C}, \mathrm{D}$ are changed to 'zero', the outputs $\mathrm{Y}_1, \mathrm{Y}_2, \mathrm{Y}_3$ respectively change to

Show answer and solution

Answer: (b)

$Y_1 = A + B$ , $Y_2 = \overline{\overline{C \cdot D}} = C \cdot D$ , $Y_3 = \overline{Y_1 + Y_2}$ .
Check: all inputs 1 give $(1, 1, 0)$ , as stated.
All inputs 0: $Y_1 = 0$ , $Y_2 = 0$ , $Y_3 = \overline{0 + 0} = 1$ .
So the answer is (b) $(0, 0, 1)$ .

Report a mistake

Logic Gates question from MHT CET 2024 (9 May, Shift 1)

More questions on Logic Gates