In the logic circuit diagram, when all the four inputs, A, B, C, D… | MHT CET 2026 (15 Apr, Shift 2)

Q32MHT CET 2026 · 15 APR · SHIFT 2Difficult

Logic Gates

In the logic circuit diagram, when all the four inputs, A, B, C, D are 'one' the outputs $Y_1, Y_2, Y_3$ are respectively (1, 1, 0). When the inputs A and C are changed to zero and B and D are still 'one', then the outputs $Y_1, Y_2, Y_3$ are respectively change to

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Answer: (b)

NOR followed by NOT gives $Y_1 = A + B$ ; the AND gives $Y_2 = CD$ ; the NOR gives $Y_3 = \overline{Y_1 + Y_2}$ .
Check: all inputs 1 gives $Y_1 = 1, Y_2 = 1, Y_3 = 0$ , as stated.
Now $A = C = 0$ , $B = D = 1$ : $Y_1 = 0 + 1 = 1$ , $Y_2 = 0 \cdot 1 = 0$ , $Y_3 = \overline{1 + 0} = 0$ .
So the answer is (b) $1, 0, 0$ .

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Logic Gates question from MHT CET 2026 (15 Apr, Shift 2)

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