In the logic circuit given, A, B and C are the inputs and Y is the output. The output Y is HIGH (a) for all the HIGH inputs. (b) for all the LOW inputs. (c) when A = 1, B = 0, C = 0 (d) when A = 1, B = 0, C = 1

Answer: (c). NOR gives B + C; AND with A gives Y = A · B + C. Y = 1 needs A = 1 and B = C = 0. So the answer is (c) A = 1, B = 0, C = 0.

In the logic circuit given, A, B and C are the inputs and Y is the… | MHT CET 2025 (22 Apr, Shift 2)

Q40MHT CET 2025 · 22 APR · SHIFT 2Medium

Logic Gates

In the logic circuit given, $\mathrm{A}, \mathrm{B}$ and C are the inputs and Y is the output. The output Y is HIGH

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Answer: (c)

NOR gives $\overline{B + C}$ ; AND with A gives $Y = A \cdot \overline{B + C}$ .
Y = 1 needs $A = 1$ and $B = C = 0$ .
So the answer is (c) $A = 1, B = 0, C = 0$ .

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