In the network shown in the figure, each of the resistance is equal to 2 Ω. The resistance between the points A and B is (a) 3 Ω (b) 4 Ω (c) 1 Ω (d) 2 Ω

Answer: (d). A is the centre and B is a corner. From A to B there are two routes through the other two corners, each 2 + 2 = 4 Ω. By symmetry those two corners are at equal potential, so the 2 Ω side joining them carries no current. RAB = 4 ∥ 4 = 2 Ω. So the answer is (d) 2 Ω.

In the network shown in the figure, each of the resistance is equal… | NEET 1995 (AIPMT)

Q83NEET 1995 · AIPMTMedium

Combination of Resistors

In the network shown in the figure, each of the resistance is equal to $2\ \Omega$ . The resistance between the points $A$ and $B$ is

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Answer: (d)

A is the centre and B is a corner. From A to B there are two routes through the other two corners, each $2 + 2 = 4\ \Omega$ .
By symmetry those two corners are at equal potential, so the $2\ \Omega$ side joining them carries no current.
$R_{AB} = 4 \parallel 4 = 2\ \Omega$ . So the answer is (d) $2\ \Omega$ .

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