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NEET 1995 (AIPMT) · Combination of Resistors

Combination of Resistors question from NEET 1995 (AIPMT)

Q83NEET 1995 · AIPMTMedium

Combination of Resistors

In the network shown in the figure, each of the resistance is equal to 2 Ω2\ \Omega. The resistance between the points AA and BB is

Figure

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Answer: (d)

  1. A is the centre and B is a corner. From A to B there are two routes through the other two corners, each 2+2=4 Ω2 + 2 = 4\ \Omega.
  2. By symmetry those two corners are at equal potential, so the 2 Ω2\ \Omega side joining them carries no current.
  3. RAB=4∥4=2 ΩR_{AB} = 4 \parallel 4 = 2\ \Omega. So the answer is (d) 2 Ω2\ \Omega.
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