In the nuclear decay given below AZX → AZ+1Y → A-4Z-1B* → A-4Z-1B, the particles emitted in the sequence are (a) γ, β, α (b) β, γ, α (c) α, β, γ (d) β, α, γ

Answer: (d). X → Y: Z up by 1, A same, so β⁻. Y → B*: A down by 4, Z down by 2, so α. B* → B: only de-excitation, so γ. So the answer is (d) β, α, γ.

In the nuclear decay given below AZX → AZ+1Y → A-4Z-1B* → A-4Z-1B… | NEET 2009 (AIPMT)

Q29NEET 2009 · AIPMTEasy

Radioactive Decays: Alpha, Beta, Gamma

In the nuclear decay given below

${}^{A}_{Z}X \rightarrow {}^{A}_{Z+1}Y \rightarrow {}^{A-4}_{Z-1}B^{*} \rightarrow {}^{A-4}_{Z-1}B,$

the particles emitted in the sequence are

Show answer and solution

Answer: (d)