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JEE Main 2021 (27 Jul, Shift 1) · Dielectrics

Dielectrics question from JEE Main 2021 (27 Jul, Shift 1)

Q83JEE Main 2021 · 27 JUL · SHIFT 1Medium

Dielectrics

In the reported figure, a capacitor is formed by placing a compound dielectric between the plates of parallel plate capacitor. The expression for the capacity of the said capacitor will be: (Given area of plate = A)

Figure

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Answer: (a)

  1. Three layers in series: dK+2d3K+3d5K=dK⋅15+10+915=34d15K\frac{d}{K}+\frac{2d}{3K}+\frac{3d}{5K}=\frac{d}{K}\cdot\frac{15+10+9}{15}=\frac{34d}{15K}
  2. C=ϵ0A34d/(15K)=1534Kϵ0AdC=\frac{\epsilon_0A}{34d/(15K)}=\frac{15}{34}\frac{K\epsilon_0A}{d}
  3. So the answer is (a).
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