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JEE Main 2025 (3 Apr, Shift 2) · Beats

Beats question from JEE Main 2025 (3 Apr, Shift 2)

Q26JEE Main 2025 · 3 APR · SHIFT 2Medium

Beats

In the resonance experiment, two air columns (closed at one end) of 100 cm and 120 cm long, give 15 beats per second when each one is sounding in the respective fundamental modes. The velocity of sound in the air column is:

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Answer: (d)

Closed pipe fundamental: $f = \frac{v}{4L}$ .
$\frac{v}{4(1.00)} - \frac{v}{4(1.20)} = 15$
$\frac{v}{4}\left(1 - \frac{5}{6}\right) = \frac{v}{24} = 15 \Rightarrow v = 360$ m/s
So the answer is (d) $360$ m/s.

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