In the series LCR circuit shown in figure the impedance is (a) 300 Ω (b) 500 Ω (c) 700 Ω (d) 900 Ω

Answer: (b). ω = 2π f = 2π × 50/π = 100 rad/s XL = ω L = 100 Ω, XC = (1)/(ω C) = 1100 × 20 × 10⁻⁶ = 500 Ω Z = √(300² + (500 - 100)²) = √(90000 + 160000) = 500 Ω So the answer is (b) 500 Ω.

In the series LCR circuit shown in figure the impedance is | MHT CET 2026 (18 Apr, Shift 2)

Q2MHT CET 2026 · 18 APR · SHIFT 2Easy

Series LCR Circuit

In the series LCR circuit shown in figure the impedance is

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Answer: (b)

$\omega = 2\pi f = 2\pi \times \frac{50}{\pi} = 100$ rad/s
$X_L = \omega L = 100\ \Omega$ , $X_C = \frac{1}{\omega C} = \frac{1}{100 \times 20 \times 10^{-6}} = 500\ \Omega$
$Z = \sqrt{300^2 + (500 - 100)^2} = \sqrt{90000 + 160000} = 500\ \Omega$
So the answer is (b) $500\ \Omega$ .

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Series LCR Circuit question from MHT CET 2026 (18 Apr, Shift 2)

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