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MHT CET 2019 (2 May, Shift 2) · Junction Transistor

Junction Transistor question from MHT CET 2019 (2 May, Shift 2)

Q83MHT CET 2019 · 2 MAY · SHIFT 2Easy

Junction Transistor

In the study of transistor as an amplifier, the ratio of collector current to emitter current is 0.98 then the ratio of collector current to base current will be

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Answer: (b)

  1. α=IC/IE=0.98\alpha = I_C/I_E = 0.98
  2. β=α1−α=0.980.02=49\beta = \frac{\alpha}{1-\alpha} = \frac{0.98}{0.02} = 49
  3. So the answer is (b) 49.
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