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MHT CET 2024 (3 May, Shift 1) · Radioactive Decays: Alpha, Beta, Gamma

Radioactive Decays: Alpha, Beta, Gamma question from MHT CET 2024 (3 May, Shift 1)

Q9MHT CET 2024 · 3 MAY · SHIFT 1Easy

Radioactive Decays: Alpha, Beta, Gamma

In the uranium radioactive series, the initial nucleus is 92238U{}^{238}_{92}\text{U} and that the final nucleus is 82206Pb{}^{206}_{82}\text{Pb}. When uranium nucleus decays into lead, the number of α\alpha-particles and β\beta-particles emitted are

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Answer: (d)

  1. nα=238−2064=8n_\alpha = \dfrac{238 - 206}{4} = 8
  2. After 8α8\alpha: Z=92−16=76Z = 92 - 16 = 76.
  3. nβ=82−76=6n_\beta = 82 - 76 = 6
  4. So the answer is (d) 8α,6β8\alpha, 6\beta.
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