In this figure the resistance of the coil of galvanometer G is 2 Ω. The emf of the cell is 4 V. The ratio of potential difference across C₁ and C₂ is: (a) 5/4 (b) 3/4 (c) 1 (d) 4/5

Answer: (d). Steady state: current flows A → 6 Ω → B → G → C → 8 Ω → D; I = (4)/(6+2+8) = 0.25 A. Drops: VAB = 1.5 V, VBC = 0.5 V, VCD = 2 V. C₁ is across A – C: V₁ = 1.5+0.5 = 2 V; C₂ is across B – D: V₂ = 0.5+2 = 2.5 V. (V₁)/(V₂) = 2/2.5, so the answer is (d) 4/5.

In this figure the resistance of the coil of galvanometer G is 2 Ω… | JEE Main 2023 (8 Apr, Shift 1)

Q20JEE Main 2023 · 8 APR · SHIFT 1Medium

Capacitors in DC Circuits & RC

In this figure the resistance of the coil of galvanometer G is $2\ \Omega$ . The emf of the cell is $4\text{ V}$ . The ratio of potential difference across $C_1$ and $C_2$ is:

Show answer and solution

Answer: (d)

Steady state: current flows $A \to 6\ \Omega \to B \to G \to C \to 8\ \Omega \to D$ ; $I = \dfrac{4}{6+2+8} = 0.25\text{ A}$ .
Drops: $V_{AB} = 1.5\text{ V}$ , $V_{BC} = 0.5\text{ V}$ , $V_{CD} = 2\text{ V}$ .
$C_1$ is across $A$ – $C$ : $V_1 = 1.5+0.5 = 2\text{ V}$ ; $C_2$ is across $B$ – $D$ : $V_2 = 0.5+2 = 2.5\text{ V}$ .
$\dfrac{V_1}{V_2} = \dfrac{2}{2.5}$ , so the answer is (d) $\dfrac{4}{5}$ .

Report a mistake

Capacitors in DC Circuits & RC question from JEE Main 2023 (8 Apr, Shift 1)

More questions on Capacitors in DC Circuits & RC