In transition 'a', three α particles and two β particles are emitted in succession from the element ₈₆X²²⁶. In transition 'b', two gamma rays, one β particle and two α particles are emitted in succession from element ₉₆Y²³⁶. The atomic number and the mass number of the new elements formed respectively are (a) a) for first transition:- atomic number = 83, mass number = 216 b) for the second transition:- atomic number = 82, mass number = 214 (b) a) for first transition:- atomic number = 80, mass number = 225 b) for the second transition:- atomic number = 90, mass number = 220 (c) a) for first transition:- atomic number = 82, mass number = 214 b) for the second transition:- atomic number = 93, mass number = 228 (d) a) for first transition:- atomic number = 80, mass number = 214 b) for the second transition:- atomic number = 90, mass number = 226

Answer: (c). Each α: Z → Z-2, A → A-4. Each β⁻: Z → Z+1, A unchanged. γ changes nothing. Transition a: 3α from ₈₆X²²⁶ gives Z = 86-6 = 80, A = 226-12 = 214; then 2β gives Z = 82, A = 214. Transition b: 2α from ₉₆Y²³⁶ gives Z = 92, A = 228; 1β gives Z = 93; the 2 gamma rays change nothing. So the answer is (c): (82, 214) and (93, 228).

In transition 'a', three α particles and two β particles are emitted… | MHT CET 2026 (12 May, Shift 1)

Q2MHT CET 2026 · 12 MAY · SHIFT 1Difficult

Radioactive Decays: Alpha, Beta, Gamma

In transition 'a', three $\alpha$ particles and two $\beta$ particles are emitted in succession from the element ${}_{86}X^{226}$ . In transition 'b', two gamma rays, one $\beta$ particle and two $\alpha$ particles are emitted in succession from element ${}_{96}Y^{236}$ . The atomic number and the mass number of the new elements formed respectively are

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Answer: (c)

Each $\alpha$ : $Z \to Z-2$ , $A \to A-4$ . Each $\beta^-$ : $Z \to Z+1$ , $A$ unchanged. $\gamma$ changes nothing.
Transition a: $3\alpha$ from ${}_{86}X^{226}$ gives $Z = 86-6 = 80$ , $A = 226-12 = 214$ ; then $2\beta$ gives $Z = 82$ , $A = 214$ .
Transition b: $2\alpha$ from ${}_{96}Y^{236}$ gives $Z = 92$ , $A = 228$ ; $1\beta$ gives $Z = 93$ ; the 2 gamma rays change nothing.
So the answer is (c): (82, 214) and (93, 228).

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Radioactive Decays: Alpha, Beta, Gamma question from MHT CET 2026 (12 May, Shift 1)

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